Optimal. Leaf size=62 \[ -\frac{2 b^2 (2-b x)^{3/2}}{105 x^{3/2}}-\frac{2 b (2-b x)^{3/2}}{35 x^{5/2}}-\frac{(2-b x)^{3/2}}{7 x^{7/2}} \]
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Rubi [A] time = 0.0080486, antiderivative size = 62, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.125, Rules used = {45, 37} \[ -\frac{2 b^2 (2-b x)^{3/2}}{105 x^{3/2}}-\frac{2 b (2-b x)^{3/2}}{35 x^{5/2}}-\frac{(2-b x)^{3/2}}{7 x^{7/2}} \]
Antiderivative was successfully verified.
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Rule 45
Rule 37
Rubi steps
\begin{align*} \int \frac{\sqrt{2-b x}}{x^{9/2}} \, dx &=-\frac{(2-b x)^{3/2}}{7 x^{7/2}}+\frac{1}{7} (2 b) \int \frac{\sqrt{2-b x}}{x^{7/2}} \, dx\\ &=-\frac{(2-b x)^{3/2}}{7 x^{7/2}}-\frac{2 b (2-b x)^{3/2}}{35 x^{5/2}}+\frac{1}{35} \left (2 b^2\right ) \int \frac{\sqrt{2-b x}}{x^{5/2}} \, dx\\ &=-\frac{(2-b x)^{3/2}}{7 x^{7/2}}-\frac{2 b (2-b x)^{3/2}}{35 x^{5/2}}-\frac{2 b^2 (2-b x)^{3/2}}{105 x^{3/2}}\\ \end{align*}
Mathematica [A] time = 0.0119495, size = 33, normalized size = 0.53 \[ -\frac{(2-b x)^{3/2} \left (2 b^2 x^2+6 b x+15\right )}{105 x^{7/2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.003, size = 28, normalized size = 0.5 \begin{align*} -{\frac{2\,{b}^{2}{x}^{2}+6\,bx+15}{105} \left ( -bx+2 \right ) ^{{\frac{3}{2}}}{x}^{-{\frac{7}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.04392, size = 59, normalized size = 0.95 \begin{align*} -\frac{{\left (-b x + 2\right )}^{\frac{3}{2}} b^{2}}{12 \, x^{\frac{3}{2}}} - \frac{{\left (-b x + 2\right )}^{\frac{5}{2}} b}{10 \, x^{\frac{5}{2}}} - \frac{{\left (-b x + 2\right )}^{\frac{7}{2}}}{28 \, x^{\frac{7}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.56232, size = 90, normalized size = 1.45 \begin{align*} \frac{{\left (2 \, b^{3} x^{3} + 2 \, b^{2} x^{2} + 3 \, b x - 30\right )} \sqrt{-b x + 2}}{105 \, x^{\frac{7}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] time = 67.6331, size = 554, normalized size = 8.94 \begin{align*} \begin{cases} \frac{2 b^{\frac{19}{2}} x^{5} \sqrt{-1 + \frac{2}{b x}}}{105 b^{6} x^{5} - 420 b^{5} x^{4} + 420 b^{4} x^{3}} - \frac{6 b^{\frac{17}{2}} x^{4} \sqrt{-1 + \frac{2}{b x}}}{105 b^{6} x^{5} - 420 b^{5} x^{4} + 420 b^{4} x^{3}} + \frac{3 b^{\frac{15}{2}} x^{3} \sqrt{-1 + \frac{2}{b x}}}{105 b^{6} x^{5} - 420 b^{5} x^{4} + 420 b^{4} x^{3}} - \frac{34 b^{\frac{13}{2}} x^{2} \sqrt{-1 + \frac{2}{b x}}}{105 b^{6} x^{5} - 420 b^{5} x^{4} + 420 b^{4} x^{3}} + \frac{132 b^{\frac{11}{2}} x \sqrt{-1 + \frac{2}{b x}}}{105 b^{6} x^{5} - 420 b^{5} x^{4} + 420 b^{4} x^{3}} - \frac{120 b^{\frac{9}{2}} \sqrt{-1 + \frac{2}{b x}}}{105 b^{6} x^{5} - 420 b^{5} x^{4} + 420 b^{4} x^{3}} & \text{for}\: \frac{2}{\left |{b x}\right |} > 1 \\\frac{2 i b^{\frac{19}{2}} x^{5} \sqrt{1 - \frac{2}{b x}}}{105 b^{6} x^{5} - 420 b^{5} x^{4} + 420 b^{4} x^{3}} - \frac{6 i b^{\frac{17}{2}} x^{4} \sqrt{1 - \frac{2}{b x}}}{105 b^{6} x^{5} - 420 b^{5} x^{4} + 420 b^{4} x^{3}} + \frac{3 i b^{\frac{15}{2}} x^{3} \sqrt{1 - \frac{2}{b x}}}{105 b^{6} x^{5} - 420 b^{5} x^{4} + 420 b^{4} x^{3}} - \frac{34 i b^{\frac{13}{2}} x^{2} \sqrt{1 - \frac{2}{b x}}}{105 b^{6} x^{5} - 420 b^{5} x^{4} + 420 b^{4} x^{3}} + \frac{132 i b^{\frac{11}{2}} x \sqrt{1 - \frac{2}{b x}}}{105 b^{6} x^{5} - 420 b^{5} x^{4} + 420 b^{4} x^{3}} - \frac{120 i b^{\frac{9}{2}} \sqrt{1 - \frac{2}{b x}}}{105 b^{6} x^{5} - 420 b^{5} x^{4} + 420 b^{4} x^{3}} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.27835, size = 82, normalized size = 1.32 \begin{align*} \frac{{\left (35 \, b^{7} + 2 \,{\left ({\left (b x - 2\right )} b^{7} + 7 \, b^{7}\right )}{\left (b x - 2\right )}\right )}{\left (b x - 2\right )} \sqrt{-b x + 2} b}{105 \,{\left ({\left (b x - 2\right )} b + 2 \, b\right )}^{\frac{7}{2}}{\left | b \right |}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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